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In the Search for the Laws of Nature

In the Search for the Laws of Nature. 124; Comments RSS. MO Diagram for F2. Posted on February 16, 2012. 24 What is Δ. 12N 2g 32H 2g. NH 3g K p 4.42. 10 4 at 25. A -26.5 kJ. Mol -1 b -11.5 kJ. Mol -1 c -2.2 kJ. Mol -1 d -0.97kJ. Here we have to use this equation ΔG -RT lnK which shows the relationship between ΔG and the equilibrium constant. The answer will be a. Sec -1 b 8. Sec -1 c 2. Sec -1 d 1. 10 -3 M. Therefore, the answer is a. 2k for the zero order,. For the third order.

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In the Search for the Laws of Nature

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In the Search for the Laws of Nature. 124; Comments RSS. MO Diagram for F2. Posted on February 16, 2012. 24 What is Δ. 12N 2g 32H 2g. NH 3g K p 4.42. 10 4 at 25. A -26.5 kJ. Mol -1 b -11.5 kJ. Mol -1 c -2.2 kJ. Mol -1 d -0.97kJ. Here we have to use this equation ΔG -RT lnK which shows the relationship between ΔG and the equilibrium constant. The answer will be a. Sec -1 b 8. Sec -1 c 2. Sec -1 d 1. 10 -3 M. Therefore, the answer is a. 2k for the zero order,. For the third order.

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The site had the following in the homepage, "In the Search for the Laws of Nature." I noticed that the web site stated " Posted on February 16, 2012." They also stated " NH 3g K p 4. Here we have to use this equation ΔG -RT lnK which shows the relationship between ΔG and the equilibrium constant. The answer will be a. Therefore, the answer is a. 2k for the zero order,."

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